Reggie left City Q for City P at 07 44. Roshel left City Q for City C at the same time. At 10 44, they were 624 km apart. Both maintained a constant speed and reached their destination at the same time at 12 14.

1. Find the distance between Cities A and C.
2. If Roshel was ⁶₇ the speed of Reggie, find Reggie's speed.

(a)
Time taken for Reggie and Roshel to travel 07 44 to 10 44 = 3 h
Time taken for Reggie and Roshel to travel 07 44 to 12 14 = 4 h 30 min = 4³⁰₆₀ h = 4¹₂ h

Distance travelled by Reggie and Roshel in 1 hour
= 624 ÷ 3
= 208 km

Total distance
= 4¹₂ x 208
= 936 km

(b)
Roshel's distance : Reggie's distance
6 : 7

Roshel's speed : Reggie's speed
6 : 7

13 u = 208 km
1 u = 208 ÷ 13 = 16 km

Reggie's speed
= 7 u
= 7 x 16
= 112 km/h

Answer(s): (a) 936 km; (b) 112km/h