Justin left City H for City G at 09 47. Xylia left City H for City C at the same time. At 13 47, they were 720 km apart. Both maintained a constant speed and reached their destination at the same time at 16 23.
- Find the distance between Cities A and C.
- If Xylia was 45 the speed of Justin, find Justin's speed.
(a)
Time taken for Justin and Xylia to travel 09 47 to 13 47 = 4 h
Time taken for Justin and Xylia to travel 09 47 to 16 23 = 6 h 36 min = 6
3660 h = 6
35 h
Distance travelled by Justin and Xylia in 1 hour
= 720 ÷ 4
= 180 km
Total distance
= 6
35 x 180
= 1188 km
(b)
Xylia's distance : Justin's distance
4 : 5
Xylia's speed : Justin's speed
4 : 5
9 u = 180 km
1 u = 180 ÷ 9 = 20 km
Justin's speed
= 5 u
= 5 x 20
= 100 km/h
Answer(s): (a) 1188 km; (b) 100km/h