Xavier left City B for City A at 07 36. Zara left City B for City C at the same time. At 10 36, they were 504 km apart. Both maintained a constant speed and reached their destination at the same time at 14 31.
- Find the distance between Cities A and C.
- If Zara was 34 the speed of Xavier, find Xavier's speed.
(a)
Time taken for Xavier and Zara to travel 07 36 to 10 36 = 3 h
Time taken for Xavier and Zara to travel 07 36 to 14 31 = 6 h 55 min = 6
5560 h = 6
1112 h
Distance travelled by Xavier and Zara in 1 hour
= 504 ÷ 3
= 168 km
Total distance
= 6
1112 x 168
= 1162 km
(b)
Zara's distance : Xavier's distance
3 : 4
Zara's speed : Xavier's speed
3 : 4
7 u = 168 km
1 u = 168 ÷ 7 = 24 km
Xavier's speed
= 4 u
= 4 x 24
= 96 km/h
Answer(s): (a) 1162 km; (b) 96km/h