Sam left City T for City S at 08 50. Opal left City T for City C at the same time. At 10 50, they were 330 km apart. Both maintained a constant speed and reached their destination at the same time at 12 14.
- Find the distance between Cities A and C.
- If Opal was 56 the speed of Sam, find Sam's speed.
(a)
Time taken for Sam and Opal to travel 08 50 to 10 50 = 2 h
Time taken for Sam and Opal to travel 08 50 to 12 14 = 3 h 24 min = 3
2460 h = 3
25 h
Distance travelled by Sam and Opal in 1 hour
= 330 ÷ 2
= 165 km
Total distance
= 3
25 x 165
= 561 km
(b)
Opal's distance : Sam's distance
5 : 6
Opal's speed : Sam's speed
5 : 6
11 u = 165 km
1 u = 165 ÷ 11 = 15 km
Sam's speed
= 6 u
= 6 x 15
= 90 km/h
Answer(s): (a) 561 km; (b) 90km/h