Reggie left City X for City W at 07 28. Nora left City X for City C at the same time. At 11 28, they were 720 km apart. Both maintained a constant speed and reached their destination at the same time at 13 23.
- Find the distance between Cities A and C.
- If Nora was 57 the speed of Reggie, find Reggie's speed.
(a)
Time taken for Reggie and Nora to travel 07 28 to 11 28 = 4 h
Time taken for Reggie and Nora to travel 07 28 to 13 23 = 5 h 55 min = 5
5560 h = 5
1112 h
Distance travelled by Reggie and Nora in 1 hour
= 720 ÷ 4
= 180 km
Total distance
= 5
1112 x 180
= 1065 km
(b)
Nora's distance : Reggie's distance
5 : 7
Nora's speed : Reggie's speed
5 : 7
12 u = 180 km
1 u = 180 ÷ 12 = 15 km
Reggie's speed
= 7 u
= 7 x 15
= 105 km/h
Answer(s): (a) 1065 km; (b) 105km/h