Seth left City D for City C at 09 48. Opal left City D for City C at the same time. At 14 48, they were 825 km apart. Both maintained a constant speed and reached their destination at the same time at 16 12.
- Find the distance between Cities A and C.
- If Opal was 56 the speed of Seth, find Seth's speed.
(a)
Time taken for Seth and Opal to travel 09 48 to 14 48 = 5 h
Time taken for Seth and Opal to travel 09 48 to 16 12 = 6 h 24 min = 6
2460 h = 6
25 h
Distance travelled by Seth and Opal in 1 hour
= 825 ÷ 5
= 165 km
Total distance
= 6
25 x 165
= 1056 km
(b)
Opal's distance : Seth's distance
5 : 6
Opal's speed : Seth's speed
5 : 6
11 u = 165 km
1 u = 165 ÷ 11 = 15 km
Seth's speed
= 6 u
= 6 x 15
= 90 km/h
Answer(s): (a) 1056 km; (b) 90km/h