Archie left City F for City E at 06 33. Opal left City F for City C at the same time. At 11 33, they were 960 km apart. Both maintained a constant speed and reached their destination at the same time at 13 28.
- Find the distance between Cities A and C.
- If Opal was 57 the speed of Archie, find Archie's speed.
(a)
Time taken for Archie and Opal to travel 06 33 to 11 33 = 5 h
Time taken for Archie and Opal to travel 06 33 to 13 28 = 6 h 55 min = 6
5560 h = 6
1112 h
Distance travelled by Archie and Opal in 1 hour
= 960 ÷ 5
= 192 km
Total distance
= 6
1112 x 192
= 1328 km
(b)
Opal's distance : Archie's distance
5 : 7
Opal's speed : Archie's speed
5 : 7
12 u = 192 km
1 u = 192 ÷ 12 = 16 km
Archie's speed
= 7 u
= 7 x 16
= 112 km/h
Answer(s): (a) 1328 km; (b) 112km/h