Billy left City T for City S at 09 38. Barbara left City T for City C at the same time. At 11 38, they were 288 km apart. Both maintained a constant speed and reached their destination at the same time at 16 33.
- Find the distance between Cities A and C.
- If Barbara was 35 the speed of Billy, find Billy's speed.
(a)
Time taken for Billy and Barbara to travel 09 38 to 11 38 = 2 h
Time taken for Billy and Barbara to travel 09 38 to 16 33 = 6 h 55 min = 6
5560 h = 6
1112 h
Distance travelled by Billy and Barbara in 1 hour
= 288 ÷ 2
= 144 km
Total distance
= 6
1112 x 144
= 996 km
(b)
Barbara's distance : Billy's distance
3 : 5
Barbara's speed : Billy's speed
3 : 5
8 u = 144 km
1 u = 144 ÷ 8 = 18 km
Billy's speed
= 5 u
= 5 x 18
= 90 km/h
Answer(s): (a) 996 km; (b) 90km/h