Riordan left City X for City W at 08 33. Jean left City X for City C at the same time. At 10 33, they were 288 km apart. Both maintained a constant speed and reached their destination at the same time at 13 23.
- Find the distance between Cities A and C.
- If Jean was 35 the speed of Riordan, find Riordan's speed.
(a)
Time taken for Riordan and Jean to travel 08 33 to 10 33 = 2 h
Time taken for Riordan and Jean to travel 08 33 to 13 23 = 4 h 50 min = 4
5060 h = 4
56 h
Distance travelled by Riordan and Jean in 1 hour
= 288 ÷ 2
= 144 km
Total distance
= 4
56 x 144
= 696 km
(b)
Jean's distance : Riordan's distance
3 : 5
Jean's speed : Riordan's speed
3 : 5
8 u = 144 km
1 u = 144 ÷ 8 = 18 km
Riordan's speed
= 5 u
= 5 x 18
= 90 km/h
Answer(s): (a) 696 km; (b) 90km/h