Reggie left City G for City F at 09 38. Lucy left City G for City C at the same time. At 11 38, they were 288 km apart. Both maintained a constant speed and reached their destination at the same time at 13 13.
- Find the distance between Cities A and C.
- If Lucy was 35 the speed of Reggie, find Reggie's speed.
(a)
Time taken for Reggie and Lucy to travel 09 38 to 11 38 = 2 h
Time taken for Reggie and Lucy to travel 09 38 to 13 13 = 3 h 35 min = 3
3560 h = 3
712 h
Distance travelled by Reggie and Lucy in 1 hour
= 288 ÷ 2
= 144 km
Total distance
= 3
712 x 144
= 516 km
(b)
Lucy's distance : Reggie's distance
3 : 5
Lucy's speed : Reggie's speed
3 : 5
8 u = 144 km
1 u = 144 ÷ 8 = 18 km
Reggie's speed
= 5 u
= 5 x 18
= 90 km/h
Answer(s): (a) 516 km; (b) 90km/h