Bryan left City Y for City X at 07 40. Eva left City Y for City C at the same time. At 11 40, they were 560 km apart. Both maintained a constant speed and reached their destination at the same time at 14 16.
- Find the distance between Cities A and C.
- If Eva was 59 the speed of Bryan, find Bryan's speed.
(a)
Time taken for Bryan and Eva to travel 07 40 to 11 40 = 4 h
Time taken for Bryan and Eva to travel 07 40 to 14 16 = 6 h 36 min = 6
3660 h = 6
35 h
Distance travelled by Bryan and Eva in 1 hour
= 560 ÷ 4
= 140 km
Total distance
= 6
35 x 140
= 924 km
(b)
Eva's distance : Bryan's distance
5 : 9
Eva's speed : Bryan's speed
5 : 9
14 u = 140 km
1 u = 140 ÷ 14 = 10 km
Bryan's speed
= 9 u
= 9 x 10
= 90 km/h
Answer(s): (a) 924 km; (b) 90km/h