Reggie left City U for City T at 08 44. Marion left City U for City C at the same time. At 10 44, they were 368 km apart. Both maintained a constant speed and reached their destination at the same time at 13 29.

1. Find the distance between Cities A and C.
2. If Marion was ³₅ the speed of Reggie, find Reggie's speed.

(a)
Time taken for Reggie and Marion to travel 08 44 to 10 44 = 2 h
Time taken for Reggie and Marion to travel 08 44 to 13 29 = 4 h 45 min = 4⁴⁵₆₀ h = 4³₄ h

Distance travelled by Reggie and Marion in 1 hour
= 368 ÷ 2
= 184 km

Total distance
= 4³₄ x 184
= 874 km

(b)
Marion's distance : Reggie's distance
3 : 5

Marion's speed : Reggie's speed
3 : 5

8 u = 184 km
1 u = 184 ÷ 8 = 23 km

Reggie's speed
= 5 u
= 5 x 23
= 115 km/h

Answer(s): (a) 874 km; (b) 115km/h