Simon left City J for City H at 09 40. Shiyun left City J for City C at the same time. At 12 40, they were 540 km apart. Both maintained a constant speed and reached their destination at the same time at 14 12.
- Find the distance between Cities A and C.
- If Shiyun was 45 the speed of Simon, find Simon's speed.
(a)
Time taken for Simon and Shiyun to travel 09 40 to 12 40 = 3 h
Time taken for Simon and Shiyun to travel 09 40 to 14 12 = 4 h 32 min = 4
3260 h = 4
815 h
Distance travelled by Simon and Shiyun in 1 hour
= 540 ÷ 3
= 180 km
Total distance
= 4
815 x 180
= 816 km
(b)
Shiyun's distance : Simon's distance
4 : 5
Shiyun's speed : Simon's speed
4 : 5
9 u = 180 km
1 u = 180 ÷ 9 = 20 km
Simon's speed
= 5 u
= 5 x 20
= 100 km/h
Answer(s): (a) 816 km; (b) 100km/h