Bryan left City M for City L at 09 45. Xylia left City M for City C at the same time. At 12 45, they were 480 km apart. Both maintained a constant speed and reached their destination at the same time at 16 27.
- Find the distance between Cities A and C.
- If Xylia was 35 the speed of Bryan, find Bryan's speed.
(a)
Time taken for Bryan and Xylia to travel 09 45 to 12 45 = 3 h
Time taken for Bryan and Xylia to travel 09 45 to 16 27 = 6 h 42 min = 6
4260 h = 6
710 h
Distance travelled by Bryan and Xylia in 1 hour
= 480 ÷ 3
= 160 km
Total distance
= 6
710 x 160
= 1072 km
(b)
Xylia's distance : Bryan's distance
3 : 5
Xylia's speed : Bryan's speed
3 : 5
8 u = 160 km
1 u = 160 ÷ 8 = 20 km
Bryan's speed
= 5 u
= 5 x 20
= 100 km/h
Answer(s): (a) 1072 km; (b) 100km/h