Valen left City L for City K at 09 40. Min left City L for City C at the same time. At 12 40, they were 540 km apart. Both maintained a constant speed and reached their destination at the same time at 15 34.
- Find the distance between Cities A and C.
- If Min was 45 the speed of Valen, find Valen's speed.
(a)
Time taken for Valen and Min to travel 09 40 to 12 40 = 3 h
Time taken for Valen and Min to travel 09 40 to 15 34 = 5 h 54 min = 5
5460 h = 5
910 h
Distance travelled by Valen and Min in 1 hour
= 540 ÷ 3
= 180 km
Total distance
= 5
910 x 180
= 1062 km
(b)
Min's distance : Valen's distance
4 : 5
Min's speed : Valen's speed
4 : 5
9 u = 180 km
1 u = 180 ÷ 9 = 20 km
Valen's speed
= 5 u
= 5 x 20
= 100 km/h
Answer(s): (a) 1062 km; (b) 100km/h