Riordan left City P for City N at 09 49. Kimberly left City P for City C at the same time. At 11 49, they were 360 km apart. Both maintained a constant speed and reached their destination at the same time at 14 22.

1. Find the distance between Cities A and C.
2. If Kimberly was ⁴₅ the speed of Riordan, find Riordan's speed.

(a)
Time taken for Riordan and Kimberly to travel 09 49 to 11 49 = 2 h
Time taken for Riordan and Kimberly to travel 09 49 to 14 22 = 4 h 33 min = 4³³₆₀ h = 4¹¹₂₀ h

Distance travelled by Riordan and Kimberly in 1 hour
= 360 ÷ 2
= 180 km

Total distance
= 4¹¹₂₀ x 180
= 819 km

(b)
Kimberly's distance : Riordan's distance
4 : 5

Kimberly's speed : Riordan's speed
4 : 5

9 u = 180 km
1 u = 180 ÷ 9 = 20 km

Riordan's speed
= 5 u
= 5 x 20
= 100 km/h

Answer(s): (a) 819 km; (b) 100km/h