Cody left City R for City Q at 09 16. Diana left City R for City C at the same time. At 11 16, they were 390 km apart. Both maintained a constant speed and reached their destination at the same time at 13 12.
- Find the distance between Cities A and C.
- If Diana was 67 the speed of Cody, find Cody's speed.
(a)
Time taken for Cody and Diana to travel 09 16 to 11 16 = 2 h
Time taken for Cody and Diana to travel 09 16 to 13 12 = 3 h 56 min = 3
5660 h = 3
1415 h
Distance travelled by Cody and Diana in 1 hour
= 390 ÷ 2
= 195 km
Total distance
= 3
1415 x 195
= 767 km
(b)
Diana's distance : Cody's distance
6 : 7
Diana's speed : Cody's speed
6 : 7
13 u = 195 km
1 u = 195 ÷ 13 = 15 km
Cody's speed
= 7 u
= 7 x 15
= 105 km/h
Answer(s): (a) 767 km; (b) 105km/h