Caden left City X for City W at 07 41. Kathy left City X for City C at the same time. At 11 41, they were 780 km apart. Both maintained a constant speed and reached their destination at the same time at 14 17.
- Find the distance between Cities A and C.
- If Kathy was 78 the speed of Caden, find Caden's speed.
(a)
Time taken for Caden and Kathy to travel 07 41 to 11 41 = 4 h
Time taken for Caden and Kathy to travel 07 41 to 14 17 = 6 h 36 min = 6
3660 h = 6
35 h
Distance travelled by Caden and Kathy in 1 hour
= 780 ÷ 4
= 195 km
Total distance
= 6
35 x 195
= 1287 km
(b)
Kathy's distance : Caden's distance
7 : 8
Kathy's speed : Caden's speed
7 : 8
15 u = 195 km
1 u = 195 ÷ 15 = 13 km
Caden's speed
= 8 u
= 8 x 13
= 104 km/h
Answer(s): (a) 1287 km; (b) 104km/h