Perry left City S for City R at 06 47. Lynn left City S for City C at the same time. At 11 47, they were 900 km apart. Both maintained a constant speed and reached their destination at the same time at 13 25.
- Find the distance between Cities A and C.
- If Lynn was 57 the speed of Perry, find Perry's speed.
(a)
Time taken for Perry and Lynn to travel 06 47 to 11 47 = 5 h
Time taken for Perry and Lynn to travel 06 47 to 13 25 = 6 h 38 min = 6
3860 h = 6
1930 h
Distance travelled by Perry and Lynn in 1 hour
= 900 ÷ 5
= 180 km
Total distance
= 6
1930 x 180
= 1194 km
(b)
Lynn's distance : Perry's distance
5 : 7
Lynn's speed : Perry's speed
5 : 7
12 u = 180 km
1 u = 180 ÷ 12 = 15 km
Perry's speed
= 7 u
= 7 x 15
= 105 km/h
Answer(s): (a) 1194 km; (b) 105km/h