Ben left City E for City D at 06 39. Sabrina left City E for City C at the same time. At 10 39, they were 624 km apart. Both maintained a constant speed and reached their destination at the same time at 12 24.
- Find the distance between Cities A and C.
- If Sabrina was 57 the speed of Ben, find Ben's speed.
(a)
Time taken for Ben and Sabrina to travel 06 39 to 10 39 = 4 h
Time taken for Ben and Sabrina to travel 06 39 to 12 24 = 5 h 45 min = 5
4560 h = 5
34 h
Distance travelled by Ben and Sabrina in 1 hour
= 624 ÷ 4
= 156 km
Total distance
= 5
34 x 156
= 897 km
(b)
Sabrina's distance : Ben's distance
5 : 7
Sabrina's speed : Ben's speed
5 : 7
12 u = 156 km
1 u = 156 ÷ 12 = 13 km
Ben's speed
= 7 u
= 7 x 13
= 91 km/h
Answer(s): (a) 897 km; (b) 91km/h