Lee left City B for City A at 09 35. Sabrina left City B for City C at the same time. At 13 35, they were 672 km apart. Both maintained a constant speed and reached their destination at the same time at 15 30.
- Find the distance between Cities A and C.
- If Sabrina was 35 the speed of Lee, find Lee's speed.
(a)
Time taken for Lee and Sabrina to travel 09 35 to 13 35 = 4 h
Time taken for Lee and Sabrina to travel 09 35 to 15 30 = 5 h 55 min = 5
5560 h = 5
1112 h
Distance travelled by Lee and Sabrina in 1 hour
= 672 ÷ 4
= 168 km
Total distance
= 5
1112 x 168
= 994 km
(b)
Sabrina's distance : Lee's distance
3 : 5
Sabrina's speed : Lee's speed
3 : 5
8 u = 168 km
1 u = 168 ÷ 8 = 21 km
Lee's speed
= 5 u
= 5 x 21
= 105 km/h
Answer(s): (a) 994 km; (b) 105km/h