Reggie left City S for City R at 06 22. Anna left City S for City C at the same time. At 11 22, they were 825 km apart. Both maintained a constant speed and reached their destination at the same time at 13 10.
- Find the distance between Cities A and C.
- If Anna was 78 the speed of Reggie, find Reggie's speed.
(a)
Time taken for Reggie and Anna to travel 06 22 to 11 22 = 5 h
Time taken for Reggie and Anna to travel 06 22 to 13 10 = 6 h 48 min = 6
4860 h = 6
45 h
Distance travelled by Reggie and Anna in 1 hour
= 825 ÷ 5
= 165 km
Total distance
= 6
45 x 165
= 1122 km
(b)
Anna's distance : Reggie's distance
7 : 8
Anna's speed : Reggie's speed
7 : 8
15 u = 165 km
1 u = 165 ÷ 15 = 11 km
Reggie's speed
= 8 u
= 8 x 11
= 88 km/h
Answer(s): (a) 1122 km; (b) 88km/h