Jenson left City C for City B at 06 50. Mary left City C for City C at the same time. At 10 50, they were 672 km apart. Both maintained a constant speed and reached their destination at the same time at 12 25.
- Find the distance between Cities A and C.
- If Mary was 35 the speed of Jenson, find Jenson's speed.
(a)
Time taken for Jenson and Mary to travel 06 50 to 10 50 = 4 h
Time taken for Jenson and Mary to travel 06 50 to 12 25 = 5 h 35 min = 5
3560 h = 5
712 h
Distance travelled by Jenson and Mary in 1 hour
= 672 ÷ 4
= 168 km
Total distance
= 5
712 x 168
= 938 km
(b)
Mary's distance : Jenson's distance
3 : 5
Mary's speed : Jenson's speed
3 : 5
8 u = 168 km
1 u = 168 ÷ 8 = 21 km
Jenson's speed
= 5 u
= 5 x 21
= 105 km/h
Answer(s): (a) 938 km; (b) 105km/h