Neave left City T for City S at 09 38. Roshel left City T for City C at the same time. At 11 38, they were 360 km apart. Both maintained a constant speed and reached their destination at the same time at 13 11.
- Find the distance between Cities A and C.
- If Roshel was 57 the speed of Neave, find Neave's speed.
(a)
Time taken for Neave and Roshel to travel 09 38 to 11 38 = 2 h
Time taken for Neave and Roshel to travel 09 38 to 13 11 = 3 h 33 min = 3
3360 h = 3
1120 h
Distance travelled by Neave and Roshel in 1 hour
= 360 ÷ 2
= 180 km
Total distance
= 3
1120 x 180
= 639 km
(b)
Roshel's distance : Neave's distance
5 : 7
Roshel's speed : Neave's speed
5 : 7
12 u = 180 km
1 u = 180 ÷ 12 = 15 km
Neave's speed
= 7 u
= 7 x 15
= 105 km/h
Answer(s): (a) 639 km; (b) 105km/h