Seth left City X for City W at 08 49. Kimberly left City X for City C at the same time. At 12 49, they were 680 km apart. Both maintained a constant speed and reached their destination at the same time at 15 43.

1. Find the distance between Cities A and C.
2. If Kimberly was ⁸₉ the speed of Seth, find Seth's speed.

(a)
Time taken for Seth and Kimberly to travel 08 49 to 12 49 = 4 h
Time taken for Seth and Kimberly to travel 08 49 to 15 43 = 6 h 54 min = 6⁵⁴₆₀ h = 6⁹₁₀ h

Distance travelled by Seth and Kimberly in 1 hour
= 680 ÷ 4
= 170 km

Total distance
= 6⁹₁₀ x 170
= 1173 km

(b)
Kimberly's distance : Seth's distance
8 : 9

Kimberly's speed : Seth's speed
8 : 9

17 u = 170 km
1 u = 170 ÷ 17 = 10 km

Seth's speed
= 9 u
= 9 x 10
= 90 km/h

Answer(s): (a) 1173 km; (b) 90km/h