Rael left City W for City V at 05 28. Tammy left City W for City C at the same time. At 10 28, they were 1050 km apart. Both maintained a constant speed and reached their destination at the same time at 12 24.
- Find the distance between Cities A and C.
- If Tammy was 78 the speed of Rael, find Rael's speed.
(a)
Time taken for Rael and Tammy to travel 05 28 to 10 28 = 5 h
Time taken for Rael and Tammy to travel 05 28 to 12 24 = 6 h 56 min = 6
5660 h = 6
1415 h
Distance travelled by Rael and Tammy in 1 hour
= 1050 ÷ 5
= 210 km
Total distance
= 6
1415 x 210
= 1456 km
(b)
Tammy's distance : Rael's distance
7 : 8
Tammy's speed : Rael's speed
7 : 8
15 u = 210 km
1 u = 210 ÷ 15 = 14 km
Rael's speed
= 8 u
= 8 x 14
= 112 km/h
Answer(s): (a) 1456 km; (b) 112km/h