David left City J for City H at 08 34. Tina left City J for City C at the same time. At 11 34, they were 585 km apart. Both maintained a constant speed and reached their destination at the same time at 14 22.
- Find the distance between Cities A and C.
- If Tina was 67 the speed of David, find David's speed.
(a)
Time taken for David and Tina to travel 08 34 to 11 34 = 3 h
Time taken for David and Tina to travel 08 34 to 14 22 = 5 h 48 min = 5
4860 h = 5
45 h
Distance travelled by David and Tina in 1 hour
= 585 ÷ 3
= 195 km
Total distance
= 5
45 x 195
= 1131 km
(b)
Tina's distance : David's distance
6 : 7
Tina's speed : David's speed
6 : 7
13 u = 195 km
1 u = 195 ÷ 13 = 15 km
David's speed
= 7 u
= 7 x 15
= 105 km/h
Answer(s): (a) 1131 km; (b) 105km/h