Asher left City Y for City X at 09 47. Gem left City Y for City C at the same time. At 13 47, they were 840 km apart. Both maintained a constant speed and reached their destination at the same time at 16 45.
- Find the distance between Cities A and C.
- If Gem was 78 the speed of Asher, find Asher's speed.
(a)
Time taken for Asher and Gem to travel 09 47 to 13 47 = 4 h
Time taken for Asher and Gem to travel 09 47 to 16 45 = 6 h 58 min = 6
5860 h = 6
2930 h
Distance travelled by Asher and Gem in 1 hour
= 840 ÷ 4
= 210 km
Total distance
= 6
2930 x 210
= 1463 km
(b)
Gem's distance : Asher's distance
7 : 8
Gem's speed : Asher's speed
7 : 8
15 u = 210 km
1 u = 210 ÷ 15 = 14 km
Asher's speed
= 8 u
= 8 x 14
= 112 km/h
Answer(s): (a) 1463 km; (b) 112km/h