Warren left City X for City W at 09 25. Xylia left City X for City C at the same time. At 12 25, they were 540 km apart. Both maintained a constant speed and reached their destination at the same time at 14 15.
- Find the distance between Cities A and C.
- If Xylia was 45 the speed of Warren, find Warren's speed.
(a)
Time taken for Warren and Xylia to travel 09 25 to 12 25 = 3 h
Time taken for Warren and Xylia to travel 09 25 to 14 15 = 4 h 50 min = 4
5060 h = 4
56 h
Distance travelled by Warren and Xylia in 1 hour
= 540 ÷ 3
= 180 km
Total distance
= 4
56 x 180
= 870 km
(b)
Xylia's distance : Warren's distance
4 : 5
Xylia's speed : Warren's speed
4 : 5
9 u = 180 km
1 u = 180 ÷ 9 = 20 km
Warren's speed
= 5 u
= 5 x 20
= 100 km/h
Answer(s): (a) 870 km; (b) 100km/h