Oliver left City V for City U at 09 44. Wendy left City V for City C at the same time. At 11 44, they were 380 km apart. Both maintained a constant speed and reached their destination at the same time at 14 20.

1. Find the distance between Cities A and C.
2. If Wendy was ⁹₁₀ the speed of Oliver, find Oliver's speed.

(a)
Time taken for Oliver and Wendy to travel 09 44 to 11 44 = 2 h
Time taken for Oliver and Wendy to travel 09 44 to 14 20 = 4 h 36 min = 4³⁶₆₀ h = 4³₅ h

Distance travelled by Oliver and Wendy in 1 hour
= 380 ÷ 2
= 190 km

Total distance
= 4³₅ x 190
= 874 km

(b)
Wendy's distance : Oliver's distance
9 : 10

Wendy's speed : Oliver's speed
9 : 10

19 u = 190 km
1 u = 190 ÷ 19 = 10 km

Oliver's speed
= 10 u
= 10 x 10
= 100 km/h

Answer(s): (a) 874 km; (b) 100km/h