Liam left City T for City S at 08 18. Sabrina left City T for City C at the same time. At 11 18, they were 576 km apart. Both maintained a constant speed and reached their destination at the same time at 13 13.
- Find the distance between Cities A and C.
- If Sabrina was 79 the speed of Liam, find Liam's speed.
(a)
Time taken for Liam and Sabrina to travel 08 18 to 11 18 = 3 h
Time taken for Liam and Sabrina to travel 08 18 to 13 13 = 4 h 55 min = 4
5560 h = 4
1112 h
Distance travelled by Liam and Sabrina in 1 hour
= 576 ÷ 3
= 192 km
Total distance
= 4
1112 x 192
= 944 km
(b)
Sabrina's distance : Liam's distance
7 : 9
Sabrina's speed : Liam's speed
7 : 9
16 u = 192 km
1 u = 192 ÷ 16 = 12 km
Liam's speed
= 9 u
= 9 x 12
= 108 km/h
Answer(s): (a) 944 km; (b) 108km/h