Bryan left City L for City K at 09 46. Sabrina left City L for City C at the same time. At 14 46, they were 825 km apart. Both maintained a constant speed and reached their destination at the same time at 16 38.

1. Find the distance between Cities A and C.
2. If Sabrina was ⁴₇ the speed of Bryan, find Bryan's speed.

(a)
Time taken for Bryan and Sabrina to travel 09 46 to 14 46 = 5 h
Time taken for Bryan and Sabrina to travel 09 46 to 16 38 = 6 h 52 min = 6⁵²₆₀ h = 6¹³₁₅ h

Distance travelled by Bryan and Sabrina in 1 hour
= 825 ÷ 5
= 165 km

Total distance
= 6¹³₁₅ x 165
= 1133 km

(b)
Sabrina's distance : Bryan's distance
4 : 7

Sabrina's speed : Bryan's speed
4 : 7

11 u = 165 km
1 u = 165 ÷ 11 = 15 km

Bryan's speed
= 7 u
= 7 x 15
= 105 km/h

Answer(s): (a) 1133 km; (b) 105km/h