Ben left City T for City S at 09 47. Sabrina left City T for City C at the same time. At 13 47, they were 660 km apart. Both maintained a constant speed and reached their destination at the same time at 15 43.
- Find the distance between Cities A and C.
- If Sabrina was 56 the speed of Ben, find Ben's speed.
(a)
Time taken for Ben and Sabrina to travel 09 47 to 13 47 = 4 h
Time taken for Ben and Sabrina to travel 09 47 to 15 43 = 5 h 56 min = 5
5660 h = 5
1415 h
Distance travelled by Ben and Sabrina in 1 hour
= 660 ÷ 4
= 165 km
Total distance
= 5
1415 x 165
= 979 km
(b)
Sabrina's distance : Ben's distance
5 : 6
Sabrina's speed : Ben's speed
5 : 6
11 u = 165 km
1 u = 165 ÷ 11 = 15 km
Ben's speed
= 6 u
= 6 x 15
= 90 km/h
Answer(s): (a) 979 km; (b) 90km/h