Ken left City M for City L at 09 45. Kathy left City M for City C at the same time. At 11 45, they were 360 km apart. Both maintained a constant speed and reached their destination at the same time at 15 29.
- Find the distance between Cities A and C.
- If Kathy was 78 the speed of Ken, find Ken's speed.
(a)
Time taken for Ken and Kathy to travel 09 45 to 11 45 = 2 h
Time taken for Ken and Kathy to travel 09 45 to 15 29 = 5 h 44 min = 5
4460 h = 5
1115 h
Distance travelled by Ken and Kathy in 1 hour
= 360 ÷ 2
= 180 km
Total distance
= 5
1115 x 180
= 1032 km
(b)
Kathy's distance : Ken's distance
7 : 8
Kathy's speed : Ken's speed
7 : 8
15 u = 180 km
1 u = 180 ÷ 15 = 12 km
Ken's speed
= 8 u
= 8 x 12
= 96 km/h
Answer(s): (a) 1032 km; (b) 96km/h