Wesley left City Q for City P at 09 43. Jade left City Q for City C at the same time. At 14 43, they were 840 km apart. Both maintained a constant speed and reached their destination at the same time at 16 38.
- Find the distance between Cities A and C.
- If Jade was 59 the speed of Wesley, find Wesley's speed.
(a)
Time taken for Wesley and Jade to travel 09 43 to 14 43 = 5 h
Time taken for Wesley and Jade to travel 09 43 to 16 38 = 6 h 55 min = 6
5560 h = 6
1112 h
Distance travelled by Wesley and Jade in 1 hour
= 840 ÷ 5
= 168 km
Total distance
= 6
1112 x 168
= 1162 km
(b)
Jade's distance : Wesley's distance
5 : 9
Jade's speed : Wesley's speed
5 : 9
14 u = 168 km
1 u = 168 ÷ 14 = 12 km
Wesley's speed
= 9 u
= 9 x 12
= 108 km/h
Answer(s): (a) 1162 km; (b) 108km/h