Henry left City J for City H at 08 49. Emma left City J for City C at the same time. At 11 49, they were 540 km apart. Both maintained a constant speed and reached their destination at the same time at 13 39.
- Find the distance between Cities A and C.
- If Emma was 45 the speed of Henry, find Henry's speed.
(a)
Time taken for Henry and Emma to travel 08 49 to 11 49 = 3 h
Time taken for Henry and Emma to travel 08 49 to 13 39 = 4 h 50 min = 4
5060 h = 4
56 h
Distance travelled by Henry and Emma in 1 hour
= 540 ÷ 3
= 180 km
Total distance
= 4
56 x 180
= 870 km
(b)
Emma's distance : Henry's distance
4 : 5
Emma's speed : Henry's speed
4 : 5
9 u = 180 km
1 u = 180 ÷ 9 = 20 km
Henry's speed
= 5 u
= 5 x 20
= 100 km/h
Answer(s): (a) 870 km; (b) 100km/h