Paul left City Z for City Y at 06 44. Tammy left City Z for City C at the same time. At 10 44, they were 720 km apart. Both maintained a constant speed and reached their destination at the same time at 13 40.
- Find the distance between Cities A and C.
- If Tammy was 45 the speed of Paul, find Paul's speed.
(a)
Time taken for Paul and Tammy to travel 06 44 to 10 44 = 4 h
Time taken for Paul and Tammy to travel 06 44 to 13 40 = 6 h 56 min = 6
5660 h = 6
1415 h
Distance travelled by Paul and Tammy in 1 hour
= 720 ÷ 4
= 180 km
Total distance
= 6
1415 x 180
= 1248 km
(b)
Tammy's distance : Paul's distance
4 : 5
Tammy's speed : Paul's speed
4 : 5
9 u = 180 km
1 u = 180 ÷ 9 = 20 km
Paul's speed
= 5 u
= 5 x 20
= 100 km/h
Answer(s): (a) 1248 km; (b) 100km/h