Mark left City K for City J at 08 40. Hazel left City K for City C at the same time. At 11 40, they were 540 km apart. Both maintained a constant speed and reached their destination at the same time at 13 35.
- Find the distance between Cities A and C.
- If Hazel was 45 the speed of Mark, find Mark's speed.
(a)
Time taken for Mark and Hazel to travel 08 40 to 11 40 = 3 h
Time taken for Mark and Hazel to travel 08 40 to 13 35 = 4 h 55 min = 4
5560 h = 4
1112 h
Distance travelled by Mark and Hazel in 1 hour
= 540 ÷ 3
= 180 km
Total distance
= 4
1112 x 180
= 885 km
(b)
Hazel's distance : Mark's distance
4 : 5
Hazel's speed : Mark's speed
4 : 5
9 u = 180 km
1 u = 180 ÷ 9 = 20 km
Mark's speed
= 5 u
= 5 x 20
= 100 km/h
Answer(s): (a) 885 km; (b) 100km/h