Fred left City E for City D at 08 48. Eva left City E for City C at the same time. At 10 48, they were 360 km apart. Both maintained a constant speed and reached their destination at the same time at 14 12.
- Find the distance between Cities A and C.
- If Eva was 78 the speed of Fred, find Fred's speed.
(a)
Time taken for Fred and Eva to travel 08 48 to 10 48 = 2 h
Time taken for Fred and Eva to travel 08 48 to 14 12 = 5 h 24 min = 5
2460 h = 5
25 h
Distance travelled by Fred and Eva in 1 hour
= 360 ÷ 2
= 180 km
Total distance
= 5
25 x 180
= 972 km
(b)
Eva's distance : Fred's distance
7 : 8
Eva's speed : Fred's speed
7 : 8
15 u = 180 km
1 u = 180 ÷ 15 = 12 km
Fred's speed
= 8 u
= 8 x 12
= 96 km/h
Answer(s): (a) 972 km; (b) 96km/h