Peter left City Q for City P at 09 43. Yen left City Q for City C at the same time. At 13 43, they were 720 km apart. Both maintained a constant speed and reached their destination at the same time at 15 29.
- Find the distance between Cities A and C.
- If Yen was 45 the speed of Peter, find Peter's speed.
(a)
Time taken for Peter and Yen to travel 09 43 to 13 43 = 4 h
Time taken for Peter and Yen to travel 09 43 to 15 29 = 5 h 46 min = 5
4660 h = 5
2330 h
Distance travelled by Peter and Yen in 1 hour
= 720 ÷ 4
= 180 km
Total distance
= 5
2330 x 180
= 1038 km
(b)
Yen's distance : Peter's distance
4 : 5
Yen's speed : Peter's speed
4 : 5
9 u = 180 km
1 u = 180 ÷ 9 = 20 km
Peter's speed
= 5 u
= 5 x 20
= 100 km/h
Answer(s): (a) 1038 km; (b) 100km/h