Owen left City U for City T at 09 49. Min left City U for City C at the same time. At 13 49, they were 728 km apart. Both maintained a constant speed and reached their destination at the same time at 16 19.
- Find the distance between Cities A and C.
- If Min was 58 the speed of Owen, find Owen's speed.
(a)
Time taken for Owen and Min to travel 09 49 to 13 49 = 4 h
Time taken for Owen and Min to travel 09 49 to 16 19 = 6 h 30 min = 6
3060 h = 6
12 h
Distance travelled by Owen and Min in 1 hour
= 728 ÷ 4
= 182 km
Total distance
= 6
12 x 182
= 1183 km
(b)
Min's distance : Owen's distance
5 : 8
Min's speed : Owen's speed
5 : 8
13 u = 182 km
1 u = 182 ÷ 13 = 14 km
Owen's speed
= 8 u
= 8 x 14
= 112 km/h
Answer(s): (a) 1183 km; (b) 112km/h