Oscar left City Z for City Y at 09 45. Gem left City Z for City C at the same time. At 12 45, they were 396 km apart. Both maintained a constant speed and reached their destination at the same time at 15 10.
- Find the distance between Cities A and C.
- If Gem was 47 the speed of Oscar, find Oscar's speed.
(a)
Time taken for Oscar and Gem to travel 09 45 to 12 45 = 3 h
Time taken for Oscar and Gem to travel 09 45 to 15 10 = 5 h 25 min = 5
2560 h = 5
512 h
Distance travelled by Oscar and Gem in 1 hour
= 396 ÷ 3
= 132 km
Total distance
= 5
512 x 132
= 715 km
(b)
Gem's distance : Oscar's distance
4 : 7
Gem's speed : Oscar's speed
4 : 7
11 u = 132 km
1 u = 132 ÷ 11 = 12 km
Oscar's speed
= 7 u
= 7 x 12
= 84 km/h
Answer(s): (a) 715 km; (b) 84km/h