Fred left City U for City T at 08 33. Julie left City U for City C at the same time. At 12 33, they were 560 km apart. Both maintained a constant speed and reached their destination at the same time at 14 18.
- Find the distance between Cities A and C.
- If Julie was 59 the speed of Fred, find Fred's speed.
(a)
Time taken for Fred and Julie to travel 08 33 to 12 33 = 4 h
Time taken for Fred and Julie to travel 08 33 to 14 18 = 5 h 45 min = 5
4560 h = 5
34 h
Distance travelled by Fred and Julie in 1 hour
= 560 ÷ 4
= 140 km
Total distance
= 5
34 x 140
= 805 km
(b)
Julie's distance : Fred's distance
5 : 9
Julie's speed : Fred's speed
5 : 9
14 u = 140 km
1 u = 140 ÷ 14 = 10 km
Fred's speed
= 9 u
= 9 x 10
= 90 km/h
Answer(s): (a) 805 km; (b) 90km/h