Asher left City T for City S at 07 28. Rachel left City T for City C at the same time. At 10 28, they were 540 km apart. Both maintained a constant speed and reached their destination at the same time at 13 24.
- Find the distance between Cities A and C.
- If Rachel was 45 the speed of Asher, find Asher's speed.
(a)
Time taken for Asher and Rachel to travel 07 28 to 10 28 = 3 h
Time taken for Asher and Rachel to travel 07 28 to 13 24 = 5 h 56 min = 5
5660 h = 5
1415 h
Distance travelled by Asher and Rachel in 1 hour
= 540 ÷ 3
= 180 km
Total distance
= 5
1415 x 180
= 1068 km
(b)
Rachel's distance : Asher's distance
4 : 5
Rachel's speed : Asher's speed
4 : 5
9 u = 180 km
1 u = 180 ÷ 9 = 20 km
Asher's speed
= 5 u
= 5 x 20
= 100 km/h
Answer(s): (a) 1068 km; (b) 100km/h