Tommy left City J for City H at 09 39. Kimberly left City J for City C at the same time. At 11 39, they were 340 km apart. Both maintained a constant speed and reached their destination at the same time at 15 33.

1. Find the distance between Cities A and C.
2. If Kimberly was ⁷₁₀ the speed of Tommy, find Tommy's speed.

(a)
Time taken for Tommy and Kimberly to travel 09 39 to 11 39 = 2 h
Time taken for Tommy and Kimberly to travel 09 39 to 15 33 = 5 h 54 min = 5⁵⁴₆₀ h = 5⁹₁₀ h

Distance travelled by Tommy and Kimberly in 1 hour
= 340 ÷ 2
= 170 km

Total distance
= 5⁹₁₀ x 170
= 1003 km

(b)
Kimberly's distance : Tommy's distance
7 : 10

Kimberly's speed : Tommy's speed
7 : 10

17 u = 170 km
1 u = 170 ÷ 17 = 10 km

Tommy's speed
= 10 u
= 10 x 10
= 100 km/h

Answer(s): (a) 1003 km; (b) 100km/h