Jack left City H for City G at 08 25. Cindy left City H for City C at the same time. At 10 25, they were 336 km apart. Both maintained a constant speed and reached their destination at the same time at 15 10.
- Find the distance between Cities A and C.
- If Cindy was 35 the speed of Jack, find Jack's speed.
(a)
Time taken for Jack and Cindy to travel 08 25 to 10 25 = 2 h
Time taken for Jack and Cindy to travel 08 25 to 15 10 = 6 h 45 min = 6
4560 h = 6
34 h
Distance travelled by Jack and Cindy in 1 hour
= 336 ÷ 2
= 168 km
Total distance
= 6
34 x 168
= 1134 km
(b)
Cindy's distance : Jack's distance
3 : 5
Cindy's speed : Jack's speed
3 : 5
8 u = 168 km
1 u = 168 ÷ 8 = 21 km
Jack's speed
= 5 u
= 5 x 21
= 105 km/h
Answer(s): (a) 1134 km; (b) 105km/h