Eric left City Y for City X at 08 30. Cathy left City Y for City C at the same time. At 12 30, they were 576 km apart. Both maintained a constant speed and reached their destination at the same time at 15 10.
- Find the distance between Cities A and C.
- If Cathy was 35 the speed of Eric, find Eric's speed.
(a)
Time taken for Eric and Cathy to travel 08 30 to 12 30 = 4 h
Time taken for Eric and Cathy to travel 08 30 to 15 10 = 6 h 40 min = 6
4060 h = 6
23 h
Distance travelled by Eric and Cathy in 1 hour
= 576 ÷ 4
= 144 km
Total distance
= 6
23 x 144
= 960 km
(b)
Cathy's distance : Eric's distance
3 : 5
Cathy's speed : Eric's speed
3 : 5
8 u = 144 km
1 u = 144 ÷ 8 = 18 km
Eric's speed
= 5 u
= 5 x 18
= 90 km/h
Answer(s): (a) 960 km; (b) 90km/h