Reggie left City Y for City X at 07 46. Jean left City Y for City C at the same time. At 12 46, they were 910 km apart. Both maintained a constant speed and reached their destination at the same time at 14 16.
- Find the distance between Cities A and C.
- If Jean was 58 the speed of Reggie, find Reggie's speed.
(a)
Time taken for Reggie and Jean to travel 07 46 to 12 46 = 5 h
Time taken for Reggie and Jean to travel 07 46 to 14 16 = 6 h 30 min = 6
3060 h = 6
12 h
Distance travelled by Reggie and Jean in 1 hour
= 910 ÷ 5
= 182 km
Total distance
= 6
12 x 182
= 1183 km
(b)
Jean's distance : Reggie's distance
5 : 8
Jean's speed : Reggie's speed
5 : 8
13 u = 182 km
1 u = 182 ÷ 13 = 14 km
Reggie's speed
= 8 u
= 8 x 14
= 112 km/h
Answer(s): (a) 1183 km; (b) 112km/h