Rael left City T for City S at 07 49. Rachel left City T for City C at the same time. At 11 49, they were 672 km apart. Both maintained a constant speed and reached their destination at the same time at 14 14.
- Find the distance between Cities A and C.
- If Rachel was 35 the speed of Rael, find Rael's speed.
(a)
Time taken for Rael and Rachel to travel 07 49 to 11 49 = 4 h
Time taken for Rael and Rachel to travel 07 49 to 14 14 = 6 h 25 min = 6
2560 h = 6
512 h
Distance travelled by Rael and Rachel in 1 hour
= 672 ÷ 4
= 168 km
Total distance
= 6
512 x 168
= 1078 km
(b)
Rachel's distance : Rael's distance
3 : 5
Rachel's speed : Rael's speed
3 : 5
8 u = 168 km
1 u = 168 ÷ 8 = 21 km
Rael's speed
= 5 u
= 5 x 21
= 105 km/h
Answer(s): (a) 1078 km; (b) 105km/h