Jenson left City A for City Z at 07 38. Jane left City A for City C at the same time. At 11 38, they were 768 km apart. Both maintained a constant speed and reached their destination at the same time at 13 23.
- Find the distance between Cities A and C.
- If Jane was 79 the speed of Jenson, find Jenson's speed.
(a)
Time taken for Jenson and Jane to travel 07 38 to 11 38 = 4 h
Time taken for Jenson and Jane to travel 07 38 to 13 23 = 5 h 45 min = 5
4560 h = 5
34 h
Distance travelled by Jenson and Jane in 1 hour
= 768 ÷ 4
= 192 km
Total distance
= 5
34 x 192
= 1104 km
(b)
Jane's distance : Jenson's distance
7 : 9
Jane's speed : Jenson's speed
7 : 9
16 u = 192 km
1 u = 192 ÷ 16 = 12 km
Jenson's speed
= 9 u
= 9 x 12
= 108 km/h
Answer(s): (a) 1104 km; (b) 108km/h